Re: [VANILLA-LIST:2048] Vanilla-2.9pl2 Released

[Mikael Sandstr|m <d4sand@dtek.chalmers.se>]

On Sun, 7 Mar 1999, Mikael Sandstr|m wrote:

> Program received signal SIGSEGV, Segmentation fault.
> 0xef5e5de8 in fgets ()
> (gdb) bt
> #0  0xef5e5de8 in fgets ()
> #1  0x2471c in CheckBypass (login=0x6cb1c "d1tim", 
>     host=0xefffee3a "leemor.dtek.chalmers.se", 
>     file=0x6e420 "/users/dtek/and/netrek/INL_Robotpl2/bin/.bypass")
>     at main.c:606
> #2  0x236c0 in main (argc=1, argv=0xefffec38) at main.c:279

Ok no help so far, so I tried a little on my own ...
CheckBypass takes 3 arguments ...
(gdb) p line_buf
$1 = "*@meson.cse.msu.edu\000\000\000\000\000\000\000\000\001", '\000'
<repeats 15 times>,
"\004\000\006£p\000\000\000\001\000\000\000\002\000\006ô\000\000\000$",
'\000' <repeats 12 times>, "\001", '\000' <repeats 23 times>,
"\001\000\006è\000\000\000\000\002\000\001\000\000\000\000\000\000\000\000\000
ïÿê\200\000\001Ä4\000\000\000\000\000\006£p\000\006§0\000\000\000\004",
'\000' <repeats 15 times>
Seems ok ....

(gdb) p bypassfile
$2 = (FILE *) 0x60068
(gdb) p *bypassfile
Cannot access memory at address 0x60068.

This is not good!

(gdb) p errno
$3 = 4

manpages gives EINTR, fopen gives 'A signal was caught during fopen().'

So it seems like fopen don't give NULL when this happens, I will try the
following code, compare it with the old one if you want to see whats
changed. If this error happens I will get it in the ERROR file too.

extern int errno;

int CheckBypass(login, host, file)
char    *login, *host, *file;
{
  FILE  *bypassfile;
  char  log_buf[64], host_buf[64], line_buf[160];
  char  *position;
  int   num1; 
  int Hits=0;


  errno = 0;
  if ((bypassfile = fopen(file, "r")) == NULL || errno != 0) {
    ERROR(1,( "No bypass file %s, errno %d\n", file, errno));
    fflush(stderr);
    return(FALSE);
  }

Any other suggestions ? or am I totaly wrong ?

/Mikael